answer is given on back of the book =301cm square
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firstly there is a rectangle of l=25m and b=6m
area of rectangle= l×b=25×6=150m²
afterthat there is a trapezium of parallel side of length 10m and 14m and height 8m
area if trapezium =sum of parallel sides×height/2
=(10+14)×8/2=96m²
at last there is another rectangle of l=10m and breadth b=5.5m
area of rectangle=l×b=10×5.5=55m²
area of figure=sum of area of(rectangle+trapezium+another rectangle)
area of figure=150+96+55=301m²
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area of figure=301cm^2
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