Math, asked by yashwanth2202, 10 months ago

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Answered by mudrabhandari1p4cb5t
1

Step-by-step explanation:

In order to keep the term inside the square root non-negative,

3x  - 4\geqslant  {x}^{2}  + 8x \\  {x}^{2}  + 5x + 4 \leqslant 0 \\ (x + 1)(x + 4) \leqslant 0 \\

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