answer it
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plz mark as brilliant
Thanks bhaiya ^^
will surely mark after someone else answers!
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hi aish!
let PQRS be a rhombus where PR and SQ are diagonals which intersect at point O.
let PR be 24 cm
so, PO = 12cm and PS = 15cm
now, By Pythagorean theorem
A²=B²+C²
15²=12² + C²
225 = 144 + C²
C² = 81
C=9cm
diagonal SQ = 9 X 2 = 18CM
Area = ½ x [ product of diagonals]
= ½ x 24 x 18
= 216 cm²
hope this helps !!
let PQRS be a rhombus where PR and SQ are diagonals which intersect at point O.
let PR be 24 cm
so, PO = 12cm and PS = 15cm
now, By Pythagorean theorem
A²=B²+C²
15²=12² + C²
225 = 144 + C²
C² = 81
C=9cm
diagonal SQ = 9 X 2 = 18CM
Area = ½ x [ product of diagonals]
= ½ x 24 x 18
= 216 cm²
hope this helps !!
tnx! ^^"
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