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answer for Q.27 is D=(2,3).
Step-by-step explanation:
ABCD is a square, so all of its sides should be of same length.
length of AB= squareroot[(5-2)^2 + (0-0)^2 ] = 3 units.
Hence, length of AD is also 3 units.
Now, points A and B lie on horizontal X axis and point C is perpendicular to AB. (by property of a square)
Hence, BC is parallel to vertical y axis.
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Thus, we need to get point D, such that it is just simply parallel to vertical Y axis as well. BC || AD || Y axis.
Since, A=(2,0).
Hence, point D can be (2,3), i.e. 3 units vertically above the point A.
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