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: If diagonal of square is 12√2, then find its perimeter ?
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let the side of the square be x
diagonal is 12√2
therefore by Pythagoras theorem
x^2+x^2= (12√2)^2
2x^2=288
x^2=144
x=12
Therefore perimeter of square is 4×12=48
hope this will help you
consider it as the brainliest
diagonal is 12√2
therefore by Pythagoras theorem
x^2+x^2= (12√2)^2
2x^2=288
x^2=144
x=12
Therefore perimeter of square is 4×12=48
hope this will help you
consider it as the brainliest
shishirayush:
Thanks
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