answer it..... please
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3
Answer:
other zero is 3.
Step-by-step explanation:
p(x)=x^2-(3-√2)x-3√2
=x^2-3x+√2x-3x
=(x+√2)(x-3).
lasradolillypa5xls:
the question is x²+(3-√2)x.... and not x²-(3-√2)x....
then put the sign of + there and solve with this method
Answered by
2
given eq. = x² + (3-√2)x - 3√2
solving equation we get,
=>x² + 3x -√2x -3√2 = 0
=> x(x + 3) - √2(x + 3) = 0
=> (x - √2)(x +3) = 0
So,
x - √2 = 0 OR x + 3 = 0
x = √2 OR x = -3
Since, √2 is already given as a zero of the above eq. the other zero of the above eq. will be -3.
Ans. The other zero of the eq. will be -3.
solving equation we get,
=>x² + 3x -√2x -3√2 = 0
=> x(x + 3) - √2(x + 3) = 0
=> (x - √2)(x +3) = 0
So,
x - √2 = 0 OR x + 3 = 0
x = √2 OR x = -3
Since, √2 is already given as a zero of the above eq. the other zero of the above eq. will be -3.
Ans. The other zero of the eq. will be -3.
there is another method to solve this problem but this is the eaiser one
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