Question

answer ittt guys plzz

Answer 1

The two isotopic forms of Chlorine are :-

$^{35}_{17}Cl$ and $^{37}_{17}Cl$

Their existence ratio is given , 3 : 1

Therefore ,

There average atomic mass

= $\frac{75}{100}$ × 35 + $\frac{25}{100}$ × 37

= $\frac{2625}{100}$ + $\frac{925}{100}$

= 26.25 + 9.25

= 35.5 u .

Therefore , the average atomic mass of Chlorine is 35.5 u .

Answer 2

$\huge \sf \color{blue}\underline{\underline{Answer }}:$
$\huge \bf \tt 35.5$
$\\ \huge \sf \color{blue}\underline{\underline{Solution }}:$
$\large \sf \color{red}{To \ calculate \: :}$

Average atomic mass of chlorine 35 and chlorine 37 ratio of isotopes 3:1

Average atomic mass of Cl =
$\\ \large \sf \frac{35×3+37×1}{3+1} \\ \\ \large \implies \frac{ 105+37}{4} \\ \\ \large \implies \frac{142}{4} \\ \\ \large \implies 35.5$