Question

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Answer 1

$\huge \sf \color{blue}\underline{\underline{Answer }}:$
$\huge \bf \tt 35.5$
$\\ \huge \sf \color{blue}\underline{\underline{Solution }}:$
$\large \sf \color{red}{To \ calculate \: :}$

Average atomic mass of chlorine 35 and chlorine 37 ratio of isotopes 3:1

Average atomic mass of Cl =
$\\ \large \sf \frac{35×3+37×1}{3+1} \\ \\ \large \implies \frac{ 105+37}{4} \\ \\ \large \implies \frac{142}{4} \\ \\ \large \implies 35.5$

Answer 2

Answer:

Average atomic mass of chlorine 35 and chlorine 37 ratio of isotopes 3:1

Average atomic mass of Cl =

\begin{gathered} \\ \large \sf \frac{35×3+37×1}{3+1} \\ \\ \large \implies \frac{ 105+37}{4} \\ \\ \large \implies \frac{142}{4} \\ \\ \large \implies 35.5 \end{gathered}

3+1

35×3+37×1

⟹

4

105+37

⟹

4

142

⟹35.5