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SakshamJain11:
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Mean of data is 50 which is equal to sum of all frequency divided by number of frequencies.
90+30+40+ f1 +f2/5 = 50
160 +f1+f2/5 = 50
let f1 and f2 be added as (f)
160+f /5 = 50
160+f = 50×5
160+f = 250
f = 250-160
f = 90
:. the sum of frequency 1 & 2 is 90
it can be distributed according to your answer in the options .....
hope it helps you ............
MARK MY ANSWER AS BRAINLIEST
90+30+40+ f1 +f2/5 = 50
160 +f1+f2/5 = 50
let f1 and f2 be added as (f)
160+f /5 = 50
160+f = 50×5
160+f = 250
f = 250-160
f = 90
:. the sum of frequency 1 & 2 is 90
it can be distributed according to your answer in the options .....
hope it helps you ............
MARK MY ANSWER AS BRAINLIEST
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