Question

answer no.5 with appropriate reason. ​

Answer 1

Answer:

Step-by-step explanation:

20

Answer 2

Answer:

1) AB = AD

BC = CD

and AC = CA

Therefore by SSS condition, △ABC≅△ADC.

2) AC = BD

AD = BC and AB = BA

Therefore by SSS condition, △ABD≅△BAC.

3) AB = AD

∠BAC=∠DAC

and AC = AC

Therefore by SAS condition, △BAC≅△DAC.

4) AD = BC

∠ DAC = ∠BCA

and AC = CA

Therefore by SAS condition, △ABC≅△ADC.