answer of both part please i am unable to solve
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heya buddy !!
it's too easy ....
1st of all we finding area of triangle.....
so by using herons formulae..
=)s=1/2(20+34+42)
s=1/2(96)
s=48
now,,herons formula is √s(s-a)(s-b)(s-c)
=)√48(48-20)(48-34)(48-42)
=)√(2*2*3*2*2)(7*2*2)(7*2)(3*2)
=)2×2×2*2*3*7
=)48×7=336m^2
now,,,,, area of field grasee by three horses.
3*22/7*7
.
and ,,,,,hey all body is unable to find it....because it's angle is not defined.....
it's too easy ....
1st of all we finding area of triangle.....
so by using herons formulae..
=)s=1/2(20+34+42)
s=1/2(96)
s=48
now,,herons formula is √s(s-a)(s-b)(s-c)
=)√48(48-20)(48-34)(48-42)
=)√(2*2*3*2*2)(7*2*2)(7*2)(3*2)
=)2×2×2*2*3*7
=)48×7=336m^2
now,,,,, area of field grasee by three horses.
3*22/7*7
.
and ,,,,,hey all body is unable to find it....because it's angle is not defined.....
amber3:
your answer is wrong
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