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we already have 2 numbers and we have to insert 5 numbers so n= 7
now a = 8 an = 26
so, we have
an= a +(n-1)×d
putting the values
26 = 8 + (7-1) ×d
which gives
d = 3
now,
a = 8
a1 = a+d
a1 = 11
a2 = a +2d
a2 = 14
a3 = 17
a4 = 20
a5 = 23
a6 = 26
hope this will help you
now a = 8 an = 26
so, we have
an= a +(n-1)×d
putting the values
26 = 8 + (7-1) ×d
which gives
d = 3
now,
a = 8
a1 = a+d
a1 = 11
a2 = a +2d
a2 = 14
a3 = 17
a4 = 20
a5 = 23
a6 = 26
hope this will help you
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