Math, asked by Anonymous, 8 months ago

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Answered by ANGEL123401
14

Solution:-

Time to fill tank 1= z/(x-y)

Tank 1 will be (x-y) full after 1 minute

Thus, capacity of "tank 2"=2(x-y)

Time to fill "tank 2"=2(x-y)/y

Q: is z/(x-y) < 2(x-y)/y

OR

is zy< 2 (x-y)^2

1.

zy<2x^2-4xy+2y^2

zy< 2(x^2-2xy+y^2)

zy< 2(x-y)^2

Sufficient.

2.

2(x-y) < (1/2)z

4 < z/(x-y)

z/(x-y) > 4

But is;

z/(x-y) < 2(x-y)/y

Can't simplify any further.

Not sufficient.

Ans: "A"

Hope it helps you...

Answered by Anonymous
3

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