Math, asked by jdjsj13, 11 months ago

answer only if u know

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Answered by Anonymous
5

Answer:-

(i) \: (a {}^{2}  + 2b { }^{2} ) \times (b - 5) = a \times (b - 5) + 7 \times (b - 5) \\  = ab - 5a + 7b - 35

(i) \: (a {}^{2}  + 2b {}^{2} ) \times (5a - 3b) = a {}^{2} (5a - 3b) + 2b {}^{2}  (5a - 3b) \\  = 5a {}^{3}  - 3a {}^{2} b + 10ab {}^{2}  - 6b {}^{3}

Answers proved for 1 and 2

Answered by bhu29
1

ab -5 a +7b-35 ¡

5a^3-3a^2b+10b^2a -6b^3

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