Question

answer the 8 th question​

Answer 1

here is ur answer hope it may help you thank-you have a NYC day

Answer 2

$area \: = 1 \div 2 \times base \times height \\ so \: area \: given = 9 \sqrt{3cm {}^{2} } \\ and \: height = 6cm \\ t herefore \: = \\ 1 \div 2 \times b \times 6 = 9 \sqrt{3cm {}^{2} } \\ 3 \times b = 9 \sqrt{3 {}^{2} } \\ b = 9 \sqrt{3cm {}^{2} } \div 3 \\ b = 3 \sqrt{3}$

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