Math, asked by TheNightHowler, 11 months ago

Answer the above question ⬆⬆⬆​

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Answered by ItzSmartyYashi
53

so, speed of passenger train is

=33km/h

speed of Express train is

=44km/h

Refer to attachment......

\huge{\underline{\underline{\mathfrak{Thank you}}}}

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Answered by 3CHANDNI339
36

 \underline \mathbb{SOLUTION}

 \underline \mathbb{GIVEN}

Let the distance travelled by express train be

  =  > \frac{132}{x}

Let distance travelled by passenger train be

 =  >  \frac{132}{x + 11}

 \underline \mathbb{ATQ,}

 =  >  \frac{132}{x + 11}  =  \frac{132}{x}  - 1

 =  >  \frac{132}{x}  -  \frac{132}{x + 11}  = 1

 =  > 132( \frac{1}{x}  -  \frac{1}{x + 11} ) = 1

 =  > 132 ( \frac{x + 11 - x}{x(x  + 11)} ) = 1

 =  > \frac{132 \times 11}{ {x - 11x}^{2} }  = 1

 =  > 1452 =  {x}^{2}  - 11x

 =  >  {x}^{2}  - 11x - 1452 = 0

 =  >  {x}^{2}  + 44x - 33x - 1452

  =  > x(x + 44) - 33(x + 44)

 =  > (x + 44)(x - 33)

if \: x  + 44 = 0 \: then \: x =  - 44

if \: x  -  33 = 0 \: then \: x =  33

 \underline \mathbb{BUT}

speed cant be negative.

 \underline \mathbb{HENCE}

Speed of the passenger train is 33km/hr.

Speed of express train is 44km/hr.

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