answer the following question
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Class size = 5
=> U - L = 5 --------(1)
Class mark = 8.5
=> (U+L) / 2 = 8.5
=> U+L = 17 -------(2)
Adding equation 1 and 2, we get
2U = 22
=> U = 11
on putting the value of U in equation 2, we get
L = 6
Upper limit = 11
Lower limit = 6
Class intervel is (6 - 11)
=> U - L = 5 --------(1)
Class mark = 8.5
=> (U+L) / 2 = 8.5
=> U+L = 17 -------(2)
Adding equation 1 and 2, we get
2U = 22
=> U = 11
on putting the value of U in equation 2, we get
L = 6
Upper limit = 11
Lower limit = 6
Class intervel is (6 - 11)
Answered by
0
Class size = 5
=> U - L = 5 --------(1)
Class mark = 8.5
=> (U+L) / 2 = 8.5
=> U+L = 17 -------(2)
Adding equation 1 and 2, we get
2U = 22
=> U = 11
on putting the value of U in equation 2, we get
L = 6
Upper limit = 11
Lower limit = 6
Class intervel is (6 - 11)
hope it helped ⚡
braínlíest please ❤️
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