Answer the question in the attachment
it's urgent be fast please tomorrow is my exam
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option (b) is the right
Explanation:
as per the question , the third part of mass 2m will move because the total momentum of the system after explosion must remain zero .
the velocity of third part v`
according to law of conservation of momentum ,
√2(mv) = 2m × v`
v` = v / √2
the total kinetic energy generation by explosion,
1/2mv²+1/2mv²+ 1/2 (2m) v`²
mv²+mv²/2
3/2mv²
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