Question

Answer this :-
.
³C₁+³C₂+³C₃ = ?

Answer 1

(a+b) ^3 = (a + b) (a² + 2ab + b²) 

So, 

(x+3) ^3=(x + 3) (x² + 6x + 9) 

On multiplying the terms using FOIL : x^3+9x^2+27x+27