answer this and will mark as brainlist..these 2 questions.. pls
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p(x) = x cube - 4x sq + x + 6
Given p( 3 ) = 0
p(3) = 3 cube - 4(3 sq) + 3 + 6
p(3) = 27 - 4(9) + 9
p(3) = 27 - 36 + 9
p(3) = 36 - 36
p(3) = 0
Therefore it is proved that p(3) = 0
Factorisation
x^3 - 4x^2 + x + 6
(x^3 - 2x^2) - (2x^2 + x + 6)
x^(x - 2) - (x - 2)(2x + 3)
Common factor is ( x - 2 ) and other is
( x^2 - 2x - 3 )
Now factorise ( x^2 - 2x - 3 )
x^2 - 3x + 1x - 3
x(x - 3) + 1(x - 3)
For this the common factor is (x - 3) and the other is (x + 1)
Therefore the factored form of......
x^3 - 4x^2 + x + 6 is (x-2) , (x-3) , (x+1)
Hope it helps u.....
Given p( 3 ) = 0
p(3) = 3 cube - 4(3 sq) + 3 + 6
p(3) = 27 - 4(9) + 9
p(3) = 27 - 36 + 9
p(3) = 36 - 36
p(3) = 0
Therefore it is proved that p(3) = 0
Factorisation
x^3 - 4x^2 + x + 6
(x^3 - 2x^2) - (2x^2 + x + 6)
x^(x - 2) - (x - 2)(2x + 3)
Common factor is ( x - 2 ) and other is
( x^2 - 2x - 3 )
Now factorise ( x^2 - 2x - 3 )
x^2 - 3x + 1x - 3
x(x - 3) + 1(x - 3)
For this the common factor is (x - 3) and the other is (x + 1)
Therefore the factored form of......
x^3 - 4x^2 + x + 6 is (x-2) , (x-3) , (x+1)
Hope it helps u.....
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