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1. In a mathematics test given to 15 students, the following marks ( out of 100) are recorded. 41 , 39 , 48 , 52 , 46 , 62 , 54 , 40 , 96 , 52 , 98 , 40 , 42 , 52 , 60
find the mean , median, and mode of this data.
2. The following observations have been arranged in ascending order. it the median of the data is 63 ,
find the value of x. 29 , 32 , 48 , 50 , x, x + 2 ,72, 78 , 84 , 95 no copied, correct✅ answer needed
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Answers
Step-by-step explanation:
Total observations =10 (even)
Median =
2
10
=5th &
2
10
+1=6
th
observations
Median =
2
5
th
+6
th
observations
63=
2
x+x+2
⇒x+1=63
⇒x=62
I hope this may help you
→ Hey Mate ,
→ Given Question : - In a mathematics test given to 15 students, the following marks ( out of 100) are recorded. 41 , 39 , 48 , 52 , 46 , 62 , 54 , 40 , 96 , 52 , 98 , 40 , 42 , 52 , 60
→ find the mean , median, and mode of this data.
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→ Given Question second :-The following observations have been arranged in ascending order. it the median of the data is 63 ,
find the value of x. 29 , 32 , 48 , 50 , x, x + 2 ,72, 78 , 84 , 95
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→ Step-by-step explanation:
→ solution : - The marks of 15 students in mathematics test are
= 41, 39, 48, 52, 46, 62, 54, 40, 96, 52, 98, 40, 42, 52, 60
→ Mean of Data = Sum of all observation / total number of observation
→ = 41 + 39 + 48 + 52 + 46 + 62 + 54 + 40 + 96 + 52 + 98
→ = 40 + 42 + 52 + 60 / 15
→ = 822 / 15 = 54 . 8
→ Arranging the scores obtained by 15 students in an ascending order,
39, 40, 40, 41, 42, 46, 48, 52, 52, 52, 54, 60, 62, 96, 98
→ As the number of observations is 15 which is odd, therefore, the median of data will be (15+1)