Question

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Answer 1

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Answer 2

$\huge{\mathsf{\underline{\underline \purple{ANSWER}}}}$

The toy is in form of a cone above a hemisphere

The surface area of the toy would be equal to

Curved surface area of cone + curved surface area of hemisphere

$= \pi \: rl + 2\pi {r}^{2}$

Height of cone 4 cm

Diameter of cone = 6cm

Radius = 3 cm

Slant height

$\sqrt{ {4}^{2} + {3}^{2} } = \sqrt{25} \\ \\ = 5$

Total surface area of toy would be

$\pi \times 3 \times 5 + 2 \times \pi \times {3}^{2}$

=33π cm²

= 103.62 cm²

Volume of the toy would be equal to

Volume of hemisphere + volume of cone

$= \frac{2}{3} \pi {r}^{ 3} + \frac{1}{3} \pi {r}^{2} h$

$= \frac{2}{3}\pi \times {3}^{3} + \frac{1}{3} \pi \times {3}^{2} \times 4$

$= 18\pi + 12\pi$

$= 30\pi \: \: {cm}^{3}$

$= 92.4 {cm}^{3}$