Answer this fast!!!!! Please help me
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Answered by
1
Hi there !
To prove :-
4-3√2 / 5 is irrational
Proof :-
Lets assume that 4-3√2 / 5 is rational
Let ,
4-3√2 / 5 = r , where r is rational.
4 - 3√2 = 5r
- 3√2 = 5r -4
√2 = 5r -4 /-3
Here ,
its very clear that RHS is rational
On the other hand , LHS is irrational.
This is a contradiction.
Hence , our assumption was wrong.
Therefore , 4-3√2 / 5 is irrational
To prove :-
4-3√2 / 5 is irrational
Proof :-
Lets assume that 4-3√2 / 5 is rational
Let ,
4-3√2 / 5 = r , where r is rational.
4 - 3√2 = 5r
- 3√2 = 5r -4
√2 = 5r -4 /-3
Here ,
its very clear that RHS is rational
On the other hand , LHS is irrational.
This is a contradiction.
Hence , our assumption was wrong.
Therefore , 4-3√2 / 5 is irrational
Answered by
2
u can prove 3√2 irrational and then rite a statement that basic operations between rational and irrational result in irrational
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