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answer is a 3/12
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Answer:
Step-by-step explanation:
Total no.of outcomes n(s) = 36
Let E be the event that the sum on two dice is a prime number
n(E) = { (1,1) (1,2) (1,4) (1,6) (2,3) (2,5) (3,4) (4,5) (5,6) }
n(E) = 9
p(E) = n(E)/n(S)
P(E) = 9/36
P(E) = 3/12 = 1/4
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