Question

answer this if can with solution .​

Answer 1

Solution :

3x/(x - 2)( x + k) = 2/(x-2) + 1/(x + k)

Let's keep the LHS as it is and solve the RHS first .

2/(x-2) + 1/(x + k)

> { 2[ x + k] + [ x - 2 ] }/{ ( x - 2)( x + k) }

> { 3x + 2k - 2}/( x - 2)( x + k)

3x/(x - 2)( x + k) = { 3x + 2k - 2}/( x - 2)( x + k)

For x ≠ 2 and x ≠ -k

The denominator can be cancelled

> 3x = 3x + 2k - 2

> 2k - 2 = 0

> 2k = 2

> k = 1 .

This is the required value of k .

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Answer : The value of k = 1 satisfies the above equation ]

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