Question

answer this propely its 8th standard questions

Answer 1

Solution:

Given&To find: the value of
(6^-1-8^-1)^-1
$(6^{-1}-8^{-1})^{-1}$
= $( \frac{1}{6} - \frac{1}{8} ) ^{-1}$
= $( \frac{8-6}{(8)(6)})^{-1}$
= $( \frac{2}{48}) ^{-1}$
=$(\frac{1}{24})^{-1}$
=$\frac{24}{1}$
=$24$ 
 
                        Hope it helps