Question

answer this question​

Answer 1

Answer: 4

Step-by-step explanation:

{(sinA/1-cosA) -( 1-cosA/sinA)}{(cosA/ 1-sinA)-(1-sinA/cosA)}

[{(sin)^1/2-(1-cosA)^2}/sinA(1-cosA)] [{cos)^1/2-(1-sinA)^2}/cosA(1-sinA)]

Answer 2

Answer:

Step-by-step explanation:

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