Question

Answer this question no 16

Answer 1

Answer:

Step-by-step explanation:

So if the roots are equal then the determinant should be equal to zero.

So D = b^2 - 4ac ...................(1)

So here,

x - 1 + (1/kx)=0

By taking LCM we get

=> (kx^2 - kx + 1)/kx = 0

By multiplying kx on both the sides we get,

=> kx^2 - kx + 1 = 0

So here,

a = k

b = -k

c = 1

So, substitute the values in eq. (1)

D = (-k)^2 - 4(k)(1)

D = k^2 - 4k

As the roots are equal the D=0

So,

k^2 - 4k = 0

(Take k common)

k(k-4)=0

So, k = 0 or 4

Now substitute the value of k in the equation kx^2 - kx + 1 = 0

If we substitute k=0 then it will not be possible to find the root.

Then, let k = 4

So,

4x^2 - 4x + 1 = 0

=>4x^2 - 2x - 2x + 1 = 0

=>2x(2x-1) - 1(2x-1) = 0

=>(2x-1)(2x-1) = 0

So, x = 1/2,1/2

Hope it helps :)