AP PERPENDICULAR TO BC , AD || BC ,THEN FIND A(∆ABC):A(∆BCD)
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Given:
AP ⊥ BC
AD || BC
∴A(△ABC)/A(△BCD)=AP×BC/AP×BC
=1/1
Hence, the ratio of A(∆ABC) and A(∆BCD) is 1 : 1.
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