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Answered by
1
s=x2-x1 = 20-10 = 10m
t = t2-t1 = 10-6 = 4s
u = 0.5 m/s = 1/2 m/s
Applying second eqn of motion ,
s = ut + 1/2*at²
10 = (1/2)(4) + (1/2)*a*4²
a = 1m/s²
t = t2-t1 = 10-6 = 4s
u = 0.5 m/s = 1/2 m/s
Applying second eqn of motion ,
s = ut + 1/2*at²
10 = (1/2)(4) + (1/2)*a*4²
a = 1m/s²
Answered by
1
Hi friend,
Total displacement= final- initial displacement
S= 10m.
Total time= final time- initial Time
T = 4secs
S= ut +1/2 at²
10= 0.5 ×4 +1/2 ×a×16
8a=8
A= 1 m/s².
So the answer is option (a).
Hope this helped you a little!!!!!
Total displacement= final- initial displacement
S= 10m.
Total time= final time- initial Time
T = 4secs
S= ut +1/2 at²
10= 0.5 ×4 +1/2 ×a×16
8a=8
A= 1 m/s².
So the answer is option (a).
Hope this helped you a little!!!!!
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