Question

answer this question with full explanation.......................


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Answer 1

Answer:

Explanation:

is given that,

d = 0.54 gm/cc

d₀ =0.6 gm/cc

t₁ = 30

t₂ = 80

=> volumetric thermal expansion:

V = V₀(1 + 3α × ∆T) [ ∵ Y = 3α ]

∆T = t₂ - t₁

= 80 - 30

= 50⁰C

=> density = mass/Volume ,

There is no change in mass with temperature change. Thus, real expansion for density,

d = d₀((1 + 3α × ∆T)

0.54 = 0.6/[1 + 3α × 50]

0.54 = 0.6/[1 + 150α]

0.54 * [1 + 150α] = 0.6

0.54 + 81α = 0.6

81α = 0.6 - 0.54

81α =  0.06

α = 0.00074074

α = 7.4074 × 10^-4 /°C