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1)given :angle C=64°,angle B=angle C - 8°, Angle A=5(a+2)° and Angle B=2(2a+7)°
to find : angle A
solution :
Angle B=angle C - 8° ______[given ]
=64° - 8°
=56°
sum of all angles in a quadrilateral =360°
angle A+angle B+ angle C + angle D=360°
5(a+2)°+56°+64°+2(2a+7)°=360°
5a+10°+56°+64°+4a+14°=360°
5a+4a=360°-(10+56+64+14)
9a=360-144°
9a=216°
a=216/9
a=24°
thus,
angle A=5(a+2)°
=5(24+2)°
=5×26
=130°
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