if p,q are tge roots of the equation x^2+k+1=0 then 1/p+1/q=
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Answered by
4
Step-by-step explanation:
▶ x² - px + q = 0
and roots are given as p and q
✴ So,
p + q = -(-p )/1
p + q = p/1
p + q = p
q = p - p
q = 0
Now,
✴ So,
pq = q/1
p = q/q
p = 0
@ Altaf
2.8
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namith2003 Ambitious
Here is your answer.....x² - px + q = 0
and roots are given as p and q
sum \: of \: the \: roots \: = \frac{ - coefficient \: of \: x}{coefficient \: of \: {x}^{2} }sumoftheroots=
coefficientofx
2
−coefficientofx
✴ So,
p + q = -(-p )/1
p + q = p/1
p + q = p
q = p - p
q = 0
Now,
product \: of \: roots \: = \frac{constant \:
✴ So,
pq = q/1
p = q/q
p = 0
2.5
Answered by
7
sorry the answer to ur question is -k
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