Math, asked by reshu8799, 11 months ago

if p,q are tge roots of the equation x^2+k+1=0 then 1/p+1/q=​

Answers

Answered by nanudhull464
4

Step-by-step explanation:

▶ x² - px + q = 0

and roots are given as p and q

✴ So,

p + q = -(-p )/1

p + q = p/1

p + q = p

q = p - p

q = 0

Now,

✴ So,

pq = q/1

p = q/q

p = 0

@ Altaf

2.8

23 votes

THANKS 40

Comments Report

namith2003 Ambitious

Here is your answer.....x² - px + q = 0

and roots are given as p and q

sum \: of \: the \: roots \: = \frac{ - coefficient \: of \: x}{coefficient \: of \: {x}^{2} }sumoftheroots=

coefficientofx

2

−coefficientofx

✴ So,

p + q = -(-p )/1

p + q = p/1

p + q = p

q = p - p

q = 0

Now,

product \: of \: roots \: = \frac{constant \:

✴ So,

pq = q/1

p = q/q

p = 0

2.5

Answered by rohit2014
7

sorry the answer to ur question is -k

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