Question

answer this questions plz don't give wrong answers to get points ​

Answer 1

Answer:

$1 \times \frac{4}{5} = \frac{9}{5}$

$2 \times \frac{4}{5} = \frac{14}{5}$

$3 \times \frac{1}{2} = \frac{7}{2}$

then,

$\frac{14}{5} - \frac{9}{5} = \frac{14 - 9}{5} = \frac{5}{5}$

so x is,

$\frac{7}{2} - \frac{5}{5} = \frac{7 - 5}{5} = \frac{2}{5}$

Answer 2

★ Solution :-

We have two methods to solve this question.

The first method is as follows,

$\sf \leadsto 1 \dfrac{4}{5} : 2 \dfrac{4}{5} :: x : 3 \dfrac{1}{2}$

$\sf \leadsto \dfrac{9}{5} : \dfrac{14}{5} :: x : \dfrac{6}{2}$

Multiply the means and extremes seperately.

$\sf \leadsto \dfrac{14}{5}x = \dfrac{9}{5} \times \dfrac{6}{2}$

$\sf \leadsto \dfrac{14x}{5} = \dfrac{63}{10}$

$\sf \leadsto 14x = \dfrac{63}{10} \times 5$

$\sf \leadsto 14x = \dfrac{63}{2}$

$\sf \leadsto x = \dfrac{63}{2} \times \dfrac{1}{14}$

$\sf \leadsto x = \dfrac{63}{28}$

$\sf \leadsto x = \dfrac{9}{4}$

$\sf \leadsto x = 2 \dfrac{1}{4}$

Now, let's find out the same value of the different method.

The second method is as follows,

$\sf \leadsto 1 \dfrac{4}{5} : 2 \dfrac{4}{5} :: x : 3 \dfrac{1}{2}$

$\sf \leadsto \dfrac{1 \dfrac{4}{5}}{2 \dfrac{4}{5}} = \dfrac{x}{3 \dfrac{1}{2}}$

$\sf \leadsto \dfrac{\dfrac{9}{5}}{\dfrac{14}{5}} = \dfrac{x}{\dfrac{7}{2}}$

$\sf \leadsto \dfrac{9}{5} \times \dfrac{5}{14} = x \times \dfrac{2}{7}$

$\sf \leadsto \dfrac{45}{70} = \dfrac{2x}{7}$

$\sf \leadsto \dfrac{2x}{7} = \dfrac{9}{14}$

$\sf \leadsto 2x = \dfrac{9}{14} \times 7$

$\sf \leadsto 2x = \dfrac{9}{2}$

$\sf \leadsto x = \dfrac{9}{2} \times \dfrac{1}{2}$

$\sf \leadsto x = \dfrac{9}{4}$

$\sf \leadsto x = 2 \dfrac{1}{4}$

Therefore, the value of x is 2¼.