Question

answer with explanation​

Answer 1

Step-by-step explanation:

In ∆ CAB , ∠CAB = 90°

seg AD is perpendicular to seg CB

(Given)

∴ ∆ CAB ~ ∆ CDA ~ ∆ ADB

( Similarly in right angled triangles)

∴ In ∆ CDA ~ ∆ ADB

∠ACD ≅∠ BAD .......(c.a.s.t) .........(1)

In ∆ CAB , C- D - B

∴ ∠ACB ≅∠BAD

hence Proved