Question

Answer with explanation.

Answer 1

Answer your question

Answer 2

Heya 06 :p

Common =_=

$a { \alpha }^{2} + b \alpha + c = 0$

$= > a \alpha + b = \frac{ - c}{ \alpha }$

Similarly with beta +_+

$\frac{1}{a \alpha + b} + \frac{1 }{a \beta + b} = \frac{1}{ \frac{ - c}{ \alpha } } + \frac{1}{ \frac{ - c}{ \beta } } = \frac{ - ( \alpha + \beta )}{c}$

$but \: ( \alpha + \beta ) = \frac{ - b}{a}$

$= > \frac{1}{a \alpha + b} + \frac{1 }{a \beta + b} = \frac{b}{ac}$

#Have a great day Mrs. xD