Chemistry, asked by Urstrulynidhii, 9 months ago

answer with explanation. otherwise don't ....​

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Answered by ramgsa
0

Answer:

76.8%

Explanation:

ionic character = dipole moment observed / dipole moment theorotical

The practical dipole moment= 1.964×10^-29

Theoretical dipole moment  = (1 electronic charge) × (interatomic distance)

                                               =1.602×10 ^-19×1.596×10^-10=2.557×10^-29

Now the fraction of practical to theoretical dipole moment will give us the value of percentage ionic character in LiH

Exp.value of dipole moment/Theoretical value of dipole moment

=1.964×10 ^-29/2.557*10^-29

=0.768

=76.8%

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