answer with explanation. otherwise don't ....
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Answer:
76.8%
Explanation:
ionic character = dipole moment observed / dipole moment theorotical
The practical dipole moment= 1.964×10^-29
Theoretical dipole moment = (1 electronic charge) × (interatomic distance)
=1.602×10 ^-19×1.596×10^-10=2.557×10^-29
Now the fraction of practical to theoretical dipole moment will give us the value of percentage ionic character in LiH
Exp.value of dipole moment/Theoretical value of dipole moment
=1.964×10 ^-29/2.557*10^-29
=0.768
=76.8%
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