Question

Answer with proper solution plz

Answer 1

Heya!!

2^a = 3^b = (12)^c = k ( Let )

2 = k^(1/a ) , 3 = k^(1/b)

(12)^c = ( 4 × 3 )^c

(12)^c = ( 2 × 2 × 3 )^c

(12)^c = {(k)^1/a × (k)^1/a × (k)1/b}^c

k= (k)^{( 1/a + 1/a + 1/b )}^c

k^(1/c) = k^{ 1/a + 1/a + 1/b }

Compare powers of k we have

1/c = ( 2/a + 1/b )

1/c = ( 1/a + 1/a + 1/b )

( 1/a + 1/b ) = 1/c - 1/a