Question

any who know's integration​

Answer 1

Actually welcome to the Concept of the integral calculus,

So we basically here begun by splitting the e^x on both side as separate denominators, so we get as

I = integration (2/e^x) dx+ integration ( e^x/e^x)dx

I = 2 .integration ( e^-x) dx + integration (1) dx

since both numerator and denomination are same, we get as 1

so further solving we get as,

I = 2.( e^-x+1 / -x+1) + x + C

where C is the integration constant