Aparticle is projected from the surface of the earth with an intial speed of 4.0 km//s.Find the maximum height attained by the particle. Radius of earth = 6400km g = 9.8 m//s^(2).
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Maximum hieght attaines by the particle will be 935.7 km
•) In this case , formula for the height (H) will be ,
H = (u)^2 / (2g - u^2 / R )
Where, u is the initial velocity ,g is the acceleration due to gravity and R is the radius of the Earth .
•) Now ,
H=(4000)^2/[19.6-(4000)^2/64*10^5]
H = 16000000 / 17.1
H = 935672.5m = 935.7 km
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