Integrate the following function (a) int_(o)^(2) 2t dt (b) int _(pi//6)^(pi//3) sin x dx (c) int _(4)^(10)(dx)/(x) (d) int _(o)^(pi) cos x dx (e) int _(1) ^(2)(2t -4) dt
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(a) =
= 2.[t²/2]₀²
= [2²-0²]
= 4
(b) = [-cosx]
= [-cos(π/3) - (-cos(π/6))]
= [-(1/2) + (/2)]
=
(c) = [㏑x]₄¹⁰
= ㏑10 - ㏑4
= ㏑
= ㏑2.5
(d) = [sinx]
= sinπ - sin0
= 0
(e)
= 2 [ t²/2 ]₁² - 4[t]₁²
= [ 2²- 1² ] - 4 [ 2 - 1 ]
= 3 - 4
= -1
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