Question

apply law of constant proportion to calculate mass of oxygen present in 9g of H2O​

Answer 1

Answer:

Well, we know that there are 3 atoms in water, one of oxygen and 2 of hydrogen. And you can determine the mass of oxygen in water

Which is 16amu while the mass of hydrogen is 1 amu (2 hydrogen means 2 amu mass)

We know total mass of water is 18 amu  so the oxygen percentage in water will be = (16/18)*100= 88.9% approxiamately 89% 

The remaining 11 % will be hydrogen 

So in 100 g of water 89 g will be of oxygen while 11 g will be of hydrogen

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