Are x=0,x=-1 the solution of the equations x2+x+1=0
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Answer:
No
Step-by-step explanation:
1) p(x)= x2+x+1
p(0)=0×2+0+1
p(0)= 0+0+1 = 1
1≠0
∴x=0 is not the solution of the equation x2+x+1=0
2) p(-1) = -1 ×2 + (-1) + 1
p(-1) = -2 -1 +1
p(-1) = -2
-2≠0
∴x=-1 is not the solution of the equation x2+x+1=0
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