α, β, γ are zeroes of cubic polynomial x³– 12x² + 44x + c. If α, β, γ are in AP, find the value of c.
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According to the question
So, Let β=a ; α=a−d & γ=a+d
Polynomial=x
3
−12x
2
+44x+c
Sum of roots=
1
−(−12)
=12
So,a−d+a+a+d=12
3a=12
a=4
Sum of products of two consecutive roots=44.
a(a−d)+a(a+d)+(a−d)(a+d)=44
a
2
−ad+a
2
+ad+a
2
−d
2
=44
3a
2
−d
2
=44
3(4)
2
−d
2
=44
d
2
=48−44=4
d=±2
So, α=a−d=
4+2
4−2
=
6
2
β=4
β=a+d=
4−2
4+2
=
2
6
So,Product (−c)=2×4×6
=−48
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