area enclosed within the ellipse 5x²+2y²=80 is
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Given : 5x^2 + 2y^2 =80
To Find : area enclosed within the ellipse
Solution:
5x² + 2y² =80
Dividing bith sides by 80
x²/16 + y²/40 = 1
=> x²/4² + y²/(2√10)² = 1
Comparing with
x²/a² + y²/b² = 1
=> a = 4
& b = 2√10
Area enclosed within the ellipse = π ab
= π (4)(2√10)
= 79.4 sq units
Area enclosed within the ellipse 5x² + 2y² =80 is 79.5 sq units
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