Question

Area of a square is 64 sq cm . perimeter of a rectangle is equal to the perimeter of this square . find the length of the rectangle if it's breadth is 6.5 cm .. which figure has greater area ? ​

Answer 1

area of square = a²

√64. = a

8 = a

perimeter of square = perimeter of rectangle

4*8 = 2(l+b)

32/2 = l + 6.5

16 - 6.5= l

10.5 = l

area of rectangle = l* b

= 10.5 * 6.5 = 68.25

area of rectangle is greater area

Answer 2

✔✔ Answer ✔✔

___________________________❤❤


✍ Area of square ✒ Side^2
✍ 64cm^2 ✒ side^2
✍ 8cm ✒ side

⏺ Perimeter ✒ 4 * side
⏺ 4 * 8
⏺ 32cm

❣ ATQ,

Perimeter of sq. = Perimeter of rec.
32cm = 2(l + b)
32cm = 2(l + 6.5)
32cm/2 = l + 6.5
16cm = l + 6.5
16 - 6.5 = l
9.5 = length

☁ Area of rectangle ✒ Length * Breath
✒ 9.5 * 6.5
✒ 61.75


✨ So the area of square is more than that of rectangle