Question

area of an right triangular is 129.5. if one of the sides containing the right angle is 14.5, find the other one

Answer 1

Area = 129.5

$\frac{1}{2} bh = 129.5 \\ \frac{1}{2} \times 14.5 \times h = 129.5 \\ h = \frac{129.5 \times 2}{14.5} \\ = 249 \div 14.5 = 17.17$