Math, asked by ajay2437, 1 year ago

Area of any rhombus shaped all ground is 5400 square metre when rohan walks along the diagonal in the playground then distance covered by him is 120 find the distance cover is completing one rotation alongside of this field

Answers

Answered by bhagyashreechowdhury
3

The distance covered by completing one rotation alongside this field is 300 m.

Step-by-step explanation:

It is given that,

The area of the rhombus-shaped playground ABCD = 5400 m²

The distance covered by Rohan along the diagonal of the playground i.e., the length of the diagonal, AC = 120 m

Therefore,  

The area of the rhombus-shaped playground = ½ * AC * BD

⇒ 5400 = ½ * 120 * BD

⇒ BD = 5400/60

BD = 90 m

We know that the diagonals of a rhombus bisect each other at 90 degrees.

AO = ½ AC = ½ * 120 = 60 m

And

BO = ½ BD = ½ * 90 = 45 m

Now, considering the right triangle AOB and applying the Pythagoras theorem, we get

AB² = AO² + BO²

⇒ AB = √[60² + 45²]

⇒ AB = √[5625]

AB = 75 m

Thus,

The distance covered by Rohan while completing one rotation alongside the playground is given by,

= Perimeter of the rhombus-shaped playground

= AB + BC + CD + DA

= 75 + 75 + 75 + 75

= 300 m

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