Question

Area of four wall in a room is 120m2. The length is twice of its breadth. If the height of room is 4m.find the area of floor.

Answer 1

l=2b
A.T.Q. LSA of four wall = 2(l+b)h
120=2(2b+b)4
120=8(3b)
15=3b
b=5m
l=10m
Area of floor =l*b
=10*5
=50m^2

Answer 2

Given:- Perimeter of the rectangular floor:-40m

Height of the room:-4m

To find:- Area of the four walls or CSA of the room.

Solution:- We know that the CSA of a cuboid:- 2h(l+b)

or:- hx2(l+b)

Also, 2(l+b)= Perimeter of the rectangle. So,

CSA of Room:- hx40

:- 4x40

:- 160m^2

#KEEPLEARNING

HOPE I AM CLEAR.

WARM REGARDS.

(≧▽≦)