area of rombus is 350cm² and one of its diagonal measures 28cm find the lenght of the other diagonal
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Area of a rhombus =21×(diagonal 1×diagonal 2)
Given, Area =28 cm2
∴21×4×diagonal 2=28 cm2
Hence, diagonal 2=14 cm
In a rhombus, the diagonals bisect each other at 900
Referring the diagram, if PR=4 cm,SQ=14 cm, then OP=2 cm,OQ=7 cm
Since, △POQ is a right angled triangle,
PQ2=OP2+OQ2⇒22+72=53
PQ=53 cm
Hence, the length of the sides of the rhombus =53 cm.
Since the length of all sides of a rhombus are equal, Perimeter =4× length of one side =4×53 cm
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Answer:
area of rhombus =1/2 x d1 x d2
350= 1/2 x 28 x d2
350/14 = d2
d2=25
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